Question 1092423
Since MO is the bisector,
{{{NMO=LMO}}}
{{{6x-27=2x+33}}}
{{{4x=60}}}
Then solve for LMN,
{{{LMN=2(2x+33)}}}
{{{LMN=4x+66}}}
You can substitute without solving for x.
{{{LMN=60+66}}}