Question 1092556
Let {{{ s }}} = his speed for the first 3 hrs
{{{ s - 25 }}} = his speed for the last hr
Let {{{ d }}} = distance in miles travels
during the first 3 hrs
{{{ 183 - d }}} = distance trveled in last hr
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(1) {{{ d = s*3 }}}
(2) {{{ 183 - d = ( s - 25 )*1 }}}
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Substitute (1) into (2)
(2) {{{ 183 - 3s = s - 25 }}}
(2) {{{ 4s = 183 + 25 }}}
(2) {{{ 4s = 208 }}}
(2) {{{ s = 52 }}}
His speed was 52 mi/hr for the first 3 hrs
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check:
(1) {{{ d = 3*52 }}}
(1) {{{ d = 156 }}} mi
and
(2) {{{ 183 - d = 52 - 25 }}}
(2) {{{ d = 183 - 27 }}}
(2) {{{ d = 156 }}} mi
OK