Question 1092468
let's look at the graph of y=(x-10)^2
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{{{ graph( 400, 300, -1, 18, -1, 70, (x-10)^2) }}}
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Note x-axis is the distance of the vase from the wall and y-axis is the
height of the vase 
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a)  the base of the vase will be where the vase touches the x-axis, that is 10 cm, therefore, the base is 10 cm from the wall
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b)  25 = x^2 -20x +100, we solve for x to find the closest distance since as we move up the vase the distance to the wall gets closer(assume the y-axis is the wall), then
x^2 -20x +75 = 0
(x-15) * (x-5) = 0
x = 15 and x = 5
we reject x = 15
the shortest distance from the top of the vase to the wall is 5 cm
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c)  this is a left shift of the equation y = (x-10)^2
from b) we know that the left shift is 5 cm
10 - 5 = 5 cm from the wall to the base
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d) y = (x-10+5)^2
y = (x-5)^2
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