Question 97129
{{{sqrt(2y + 7) + 4 = y}}}
{{{sqrt(2y + 7) = y - 4}}}
{{{2y + 7 = (y - 4)^2}}}
{{{2y + 7 = y^2 - 8y + 16}}}
{{{0 = y^2 - 10y + 9}}}
{{{0 = (y - 9)(y - 1)}}}
y = 9 and y = 1
y = 1 doesn't work ... y = 9 is the only answer