Question 1092310
<br>A quadratic polynomial with x-intercepts a and b is of the form
{{{P(x) = c(x-a)(x-b)}}}
where c is some constant.<br>
In your problem, with x-intercepts at -3 and 1, the polynomial is
{{{P(x) = c(x+3)(x-1)}}}<br>
To determine the value of the constant c, use the given information that the y-intercept (which is P(0)) is 2:
{{{c(3)(-1) = 2}}}
{{{-3c = 2}}}
{{{c = -2/3}}}<br>
And the complete polynomial (in factored form) is
{{{P(x) = (-2/3)(x+3)(x-1)}}}<br>