Question 1092303
.
Write the standard equation of the circle with the given center


{{{(x-2)^2 + (y-(-6))^2}}} = {{{r^2}}},


and find "r" as the distance between the given points


r = {{{sqrt((6-2)^2 + (-1-(-6))^2)}}} = {{{sqrt(4^2 + 5^2)}}} = {{{sqrt(41)}}}.


So the final equation is {{{(x-2)^2 + (y+6)^2}}} = 41.