Question 97112
For the expression {{{ (x-8)/(x+6) }}} <0 to be true 

we have 2 cases:

case 1: numerator >0 , denominator < 0

so we have x-8 > 0 or x>8 
and x+6< 0 or x<-6 

Clearly no such x satisfies both the conditions simultaneously

case 2: numerator < 0 , denominator > 0

so we have x-8 < 0 or x < 8
and x+6 > 0 or x> -6

so we have -6< x < 8 or (-6,8) as the solution set