Question 1092238

 let sides be {{{a}}},{{{b}}}, and {{{c}}}

let {{{a}}} be the shortest 

if one side of triangle is {{{6 }}} more than {{{2}}} times the shortest side, we have
{{{b=2a+6}}}

if the third side is {{{16}} centimeters more than the shortest side, we have

{{{c=a+16}}}

 if the perimeter is {{{66}}}, we have

{{{a+b+c=66}}} 

{{{a+2a+6+a+16=66}}} 

{{{4a+22=66}}} 

{{{4a=66-22}}} 

{{{4a=44}}} 

{{{highlight(a=11)}}} 

{{{b=2a+6}}}->{{{b=2*11+6}}}->{{{highlight(b=28)}}}

{{{c=a+16}}}->{{{c=11+16}}}->{{{highlight(c=27)}}}