Question 1092185
<br>I interpret the problem differently than the tutor who posted the first response.  The way I read the problem, the size of the group is irrelevant.<br>
If the probability of any one child liking lima beans is 1/x, then the probability that two children will both like lima beans is (1/x)^2.<br>
Since the book says the probability of two children both liking lima beans is 1/16, which is (1/4)^2, I'm wondering if the problem said that the probability of any child liking lima beans is 1/4 -- instead of 4%.<br>
If 4% is indeed the probability for each child, then the probability that two children will both like lima beans is (4/100)^2 = 16/10000 = 0.0016 = 0.16%