Question 1091483
At {{{t=0}}}, {{{v=0}}}.
At {{{t=10}}},{{{v=at=2(10)=20}}}{{{m/s}}}.
At {{{t=30}}},{{{v=20}}}{{{m/s}}}.
At {{{t=40}}},{{{v=0}}}.
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 *[illustration dx3.JPG].
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The distance covered is equal to the area under the velocity vs time graph.
Find the area of the two triangles and one rectangle.
{{{A=2*(1/2)(10)(20)+(20)(20)}}}
{{{A=200+400}}}
{{{A=600m}}}