Question 1092129

({{{4}}},{{{y}}}) and ({{{-3}}},{{{-6}}}); 
slope:{{{m=15/7}}}

{{{y=mx+b}}} where {{{m}}} is a slope and {{{b}}} is y-intercept

{{{y=mx+b}}} plug in {{{m=15/7}}} and coordinates of given point ({{{-3}}},{{{-6}}}) to find  {{{b}}}

{{{-6=(15/7)(-3)+b}}}

{{{-6=-45/7+b}}}

{{{-6+45/7=b}}}

{{{-42/7+45/7=b}}}

{{{3/7=b}}}


so, your equation is:{{{y=(15/7)x+3/7}}}

now find y coordinates of the point ({{{4}}},{{{y}}})

{{{y=(15/7)4+3/7}}}

{{{y=60/7+3/7}}}

{{{y=63/7}}}

{{{y=9}}}-> the point is ({{{4}}},{{{9}}})


{{{drawing( 600, 600, -10,10, -10, 10,
circle(4,9,.12),locate(4,9,p(4,9)),
circle(-3,-6,.12),locate(-3,-6,p(-3,-6)),
 graph( 600, 600, -10,10, -10, 10, (15/7)x+3/7)) }}}