Question 1092093
1.{{{K+D+J=100}}}
2.{{{J=5+K}}}
3.{{{D=3J}}}
From 2,
{{{K=J-5}}}
Substitute this and 3 into 1,
{{{(J-5)+(3J)+J=100}}}
{{{5J=105}}}
Solve for J then use the other equations to solve for D and K.