Question 1092005

{{{2x+5+(1/2)(6x-1)=-(1/2) }}}........first, both sides multiply by {{{2}}} to get rid of fractions

{{{2*2x+2*5+2(1/2)(6x-1)=-2(1/2) }}}


{{{4x+10+cross(2)(1/cross(2)1)(6x-1)=-cross(2)(1/cross(2)1) }}}


{{{4x+10+(6x-1)=-1 }}}

{{{4x+10+6x-1=-1 }}}

{{{10x+9=-1 }}}

{{{10x=-1 -9}}}

{{{10x=-10}}}

{{{x=-10/10}}}

{{{x=-1}}}