Question 1091989
given: 
{{{t[2] =9/2}}} and {{{t[5] = 6}}}

{{{ t[1] + d = 9/2}}}......(1) where {{{t[1]}}} is first term and {{{d}}} common difference

{{{t + 4d = 6}}}........(2)


Subtract (1) from (2

{{{3d = 3/2}}}

{{{d = 1/2}}}

Sub in (1)

{{{t[1] + 1/2 = 9/2}}}

{{{t[1] = 4}}}->first term {{{

Third term {{{t[3]= t[1] + 2d}}}

{{{t[3]= 4 + 2(1/2)}}}

{{{t[3]= 5 }}}


so, your answer is A. {{{5}}}