Question 1091908
Where on the x-axis do they intersect?


{{{(2/3)x+6=0}}}
{{{x+(3/2)6=0}}}
{{{x+9=0}}}
{{{x=-9}}}
Intersect at (-9,0).


Other line is perpendicular to given line.
{{{y=(-3/2)x+b}}}
{{{b=y+(3/2)x}}}
{{{b=0+(3/2)(-9)}}}
{{{b=-27/2}}}
-
{{{highlight(y=-(3/2)x-27/2)}}}



{{{graph(300,300,-10,4,-6,7,(2/3)x+6,-3x/2-27/2)}}}