Question 1091869
A triangle has three sides, they are a, b, and c (lower case, upper case is used for angles)
Now just turn the words into algebra, like this:
One side: a
shortest side: b
third side: c
and it says that:
a = b+3
c = 2b-2
so the problem references all sides to b. Piece of cake!
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a+b+c = 17 substitute like this:
b+3+b+2b-2 = 17
4b+1 = 17
4b = 16
b = 4 so now we know that b = 4, lets find the others:
a = b+3 = 4+3 = 7
c = 2b-2 = 2(4)-2 = 8-2 = 6
Now that we have all our values, let's check and make sure we've got the right numbers:
a+b+c = 17
7+4+6 = 17 add the left side and you'll see I've got the correct answer.
:
Happy learning,
John