Question 1091801
We can use the formulas a = x 2 – y 2, b = 2xy, c = x 2 + y 2 to answer this question. Let the legs of the right triangle be a and b and the hypothenus be c, then by the pythagoras theorem
a^2+b^2=c^2

Given that
a =x^2-y^2

Let a = 11, then
x^2-y^2=11

By trial and error, we can find that the value of x = 6 and the value of y = 5.
i.e.
x^2-y^2=6^2-5^2=36-25=11

Thus,
b = 2(6)(5) = 60
and
x^2+y^2=6^2+5^2=36+25=61
Therefore, the other leg = 60 and the hypotenuse = 61.
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