Question 1091458
C:({{{x}}},{{{y}}})
D:({{{sqrt(2)}}},{{{1}}})
E:({{{-3}}},{{{-2}}})
So,
{{{sqrt(2)=(x+(-3))/2}}}
{{{x-3=2sqrt(2)}}}
{{{x=3+2sqrt(2)}}}
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{{{1=(y+(-2))/2}}}
{{{2=y-2}}}
{{{y=4}}}
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 *[illustration TS1.JPG].