Question 1091647
Let n be the speed Greg drove during the rainstorm. Then, his speed after the skies had cleared would be n+4. So:
282/n + 204/n+4=10
282n+1128+204n=10(n²+4n)
10n²-446n-1128=0
5n²-223n-564=0
(5n+12)(n-47)=0
n=-12/5, 47
Greg drove at 47 mph during the rain, and 51 mph after.
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