Question 96972
Let the first segment be x km 
therefore the second segment is 90- x km

time taken to cover the first segment (t1) = x/10
time taken to cover the second segment (t2) = (90-x)/25

given that the time taken to cover the first segment is 2 hours more

t1 = t2 + 2

substituting the values of t1 andf t2 from above 

x/10 = (90-x)/25 +2 
Multipying by 50 on both sides 

5x = 180 -2x + 100

7x =280
x=40

therefore the other segment is 90 -40 = 50

hence the segments is (40, 50)