Question 1091591


{{{sqrt((3x-1)/2)= 4}}}...I guess you mean that

{{{sqrt((3x-1)/2)= 4}}}....square both sides

{{{(sqrt((3x-1)/2))^2= 4^2}}}

{{{(3x-1)/2= 16}}}

{{{3x-1= 16*2}}}

{{{3x= 32+1}}}

{{{3x= 33}}}

{{{x= 33/3}}}

{{{x= 11}}}