Question 1091497
The equation gives you most of the information already.


{{{8(y+2)=(x+3)^2}}}, axis of symmetry is vertical. Vertex is a minimum point of the parabola.

VERTEX  (-3,-2)
p, distance between vertex and either directrix or focus;
{{{4p=8}}}, {{{p=2}}}

FOCUS (-3,0)
DIRECTRIX {{{y=-4}}}.


If solve for x when y is 0, find  zeros at x=-7 and x=1.




{{{graph(300,300,-11,5,-8,8,-2+(1/8)(x+3)^2)}}}