Question 1091542

 {{{((x^4*y^2)^(-1/2))/((x^6*y^3)^(-1/3))}}}



={{{(1/sqrt(x^4*y^2))/(1/root(3,(x^6*y^3)))}}}



={{{root(3,(x^6*y^3))/sqrt(x^4*y^2)}}}


={{{root(3,(x^2)^3*y^3)/sqrt((x^2)^2*y^2)}}}


={{{(x^2*y)/(x^2*y)}}}


={{{1}}}