Question 1091518
The first line is over the second line in a fraction.

{{{ 2x^2y^4(4x^2y^4)(3x) }}}
{{{ 3x^-3y^2 }}}
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Write it like this:
{{{ (2x^2y^4(4x^2y^4)(3x))/(3x^-3y^2) }}}
= {{{(6x^3y^4(4x^2y^4))/(3x^-3y^2) }}}
= {{{(24x^5y^8)/(3x^-3y^2) }}}
Cancel the 3's
= {{{(8x^5y^8)/(x^-3y^2) }}}
Multiply NUM and DEN by x^3
= {{{(8x^8y^8)/y^2}}}
Mutliply NUM and DEN by y^-2
= {{{8x^8y^6}}}
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the order in which you do things doesn't matter.