Question 1091498
First put the equations for the two ellipses in standard form, (x/a)^2+(y/b)^2=1
The area comprising the seats is the intersection of the two regions bounded by the inner and outer ellipse
The inner ellipse in standard form is:
x^2 + 4y^2 >= 100 -> x^2/100 + 4y^2/100 >= 1 -> (x/10)^2 + (y/5)^2 >= 1
The outer ellipse in standard form is:
(25/3600)x^2 + (36/3600)y^2 <= 1 -> (x/12)^2 + (y/10)^2 <= 1
The difference in the two areas is:
pi*12*10 - pi*10*5 = pi*70 = 219.91, but since each unit represents 10 m, we multiply by 100 m^2 to get the area:
A = 21991 m^2
Since each set occupies 0.8 m^2, there are A/0.8 = 27488.94 which rounds down to 27488 seats