Question 1091302
<br>The correct inequality is
{{{(cos(x)^2-sin(x)^2)/(cos(x)^2+sin(x)cos(x)) = 1 - tan(x)}}}<br>
Factor the numerator and denominator on the left.  The numerator factors as a difference of squares, like
{{{x^2-y^2 = (x+y)(x-y)}}}<br>
In the denominator you can factor out a common factor between the two terms.<br>
When you have done the factoring, the path to finishing the problem should be easy.