<PRE><B>Question 1091369</B>
The sum of the square of a number and seven times another number is equal to 70.
x^2 + 7y = 70
7y = 70 - x^2
y = {{{((70-x^2))/7}}}
graphically
{{{ graph( 300, 300, -15, 15, -15, 15, (70-x^2)/7, 4.86) }}}  
:
Find the minimum difference between the same two numbers.
This occurs when x=6 then y=4.86 (green line)
 Find the two numbers that achieve this minimum value.
6 - 4.86 = 1.14 is minimum difference</PRE>