Question 1091414

given: 
 {{{log(7)=0.8451}}} and
 {{{log(6)=0.7782}}}

 find: 
{{{log (25.2 )}}}.......write {{{(25.2 )}}} as {{{ (252/10 )}}}

={{{log (252/10 )}}}......write {{{(252 )}}} as {{{ (7*6^2 )}}}

={{{log ((7*6^2)/10 )}}}

={{{log ((7^2*6))-log((10 ))}}}

={{{log ((7))+log((6^2))-log((10 ))}}}

={{{log ((7))+2log((6))-log((10 ))}}}...substitute given values

={{{0.8451+2*0.7782-1}}}

={{{1.4015}}}