Question 1091335

 {{{(cos^2 (theta) - sin^2 (theta))/(cos^2 (theta )+ sin( theta) cos (theta)) = 1 - tan (theta )}}}


 {{{((cos (theta) - sin (theta))(cos (theta) + sin (theta)))/(cos (theta )(cos (theta)+ sin( theta) )) = 1 - tan (theta )}}}


 {{{((cos (theta) - sin (theta))cross((cos (theta) + sin (theta))))/(cos (theta )cross((cos (theta)+ sin( theta) ))) = 1 - tan (theta )}}}


 {{{(cos (theta) - sin (theta))/cos(theta ) = 1 - tan (theta )}}}


 {{{cos(theta)/cos (theta ) - sin (theta)/cos (theta ) = 1 - tan (theta )}}}


 {{{1 - tan (theta ) = 1 - tan (theta )}}}