Question 1091272
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List the first six terms of the sequence defined by bn= (2*4*6 …2n)/2^n.
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1-st term, n= 1:  {{{b[1]}}} = {{{2/2^1}}} = {{{2/2}}} = 1.

2-nd term, n= 2:  {{{b[2]}}} = {{{(2*4)/2^2}} = {{{8/4}}} = 2.

3-nd term, n= 3:  {{{b[3]}}} = {{{(2*4*6)/2^3}} = {{{48/8}}} = 6.

4-th term, n= 4:  {{{b[4]}}} = {{{(2*4*6*8)/2^4}} = {{{384/16}}} = 24.


Can you complete the assignment from this point on your own ?
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