Question 1091270
given:

({{{5}}},{{{7}}}) and ({{{9}}},{{{y}}}); slope {{{-5/2}}}

use slope-point formula

{{{y-y[1]=m(x-x[1])}}} ...since given {{{m=-5/2}}} and ({{{5}}},{{{7}}}) we can find equation of a line

{{{y-7=-(5/2)(x-5)}}}

{{{y-7=-(5/2)x-(5/2)(-5)}}}

{{{y-7=-(5/2)x+25/2}}}

{{{y=-(5/2)x+25/2+7}}}

{{{y=-(5/2)x+25/2+14/2}}}

{{{y=-(5/2)x+39/2}}}

now find {{{y}}} for ({{{9}}},{{{y}}})

{{{y=-(5/2)9+39/2}}}

{{{y=-45/2+39/2}}}

{{{y=-6/2}}}

{{{y=-3}}}

so, your point is ({{{9}}},{{{-3}}})


{{{drawing( 600, 600, -10, 15, -10, 10,
circle(9,-3,.12),circle(5,7,.12),
locate(9,-3,p(9,-3)),locate(5,7,p(5,7)),
 graph( 600, 600, -10, 15, -10, 10, -(5/2)x+39/2)) }}}