Question 96924
(x^2-a/x)/(a^2-a/x)

= [(x^3-a)/x] / [(a^2x -a)/x]

Invert the denominator and multiply to get:

= [[(x^3-a)/x] * [x/(a^2x -a)]

Cancel the common "x" factor in the numerator and denominator to get:

= (x^3-a)/(a^2x-a)

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Cheers,
Stan H.