<PRE><B>Question 1090862</B>
A special rubber ball is dropped from the top of a building 81m high. if after the falling it bounces back to two-thirds of the previous bouncing height, then
how high will it bounce the 5th time?
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81 m *(2/3)^5 = 81*32/243 = 32/3 meters
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what is the total distance it has covered the 6th time it touch the ground?
Find the height of each bounce.
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0th - 81 meters (when released)
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bounces:
1st - 81*2/3 = 54 up, 54 down
2nd - 54*2/3 = 36
3rd - 36*2/3 = 24
4th - 24*2/3 = 16
5th - 16*2/3 = 32/3
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Add 1st thru 5th = 422/3 meters up and down
Times 2 = 844/3 meters traveled.
+ the 81 meter drop --&gt; 1087/3 meters
=~ 362.333 meters

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