Question 1090822
points
r=0, f(r)=0
1, -1
2, 0
3, 3
-2, 8
The roots are 0 and 2, and the function is 0 for both.
The intercept is (0, 0)
the vertex is at -b/2a, b=-2, a=1 or 2/2=1 and f (1)= -1, so the vertex is at (1, -1)
graph
{{{graph(300,300,-10,10,-10,10,x^2-2x)}}}