Question 1090788
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8  gallons of 55% acid solution contain 0.55*8 gallons of the pure acid.

12 gallons of 65% acid solution contain 0.65*12 gallons of the pure acid.


The mixture contains  0.55*8 + 0.65*12  gallons of the pure acid and has the volume of 8 + 12 = 20 gallons.


Therefore, the concentration under the question is  {{{((0.55*8 + 0.65*12)/(8+20))*100}}} percents.


          Notice that I multiplied by 100 to get the percentage instead of fraction.



You complete all necessary calculations.
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