Question 1090712
<pre>
3 7 14 27 52

Subtract the integers starting with 0, which has nth term n-1

0 1  2  3  4

That gives:

3 6 12 24 48     

That's a geometric series with nth term 3&#8729;2<sup>n-1</sup>

So the general term is

3&#8729;2<sup>n-1</sup> + n - 1

Checking by substituting n=1...5

3&#8729;2<sup>1-1</sup> + 1 - 1 = 3&#8729;2<sup>0</sup>+0 = 3&#8729;1 = 3
3&#8729;2<sup>2-1</sup> + 2 - 1 = 3&#8729;2<sup>1</sup>+1 = 3&#8729;2+1 = 6+1 = 7
3&#8729;2<sup>3-1</sup> + 3 - 1 = 3&#8729;2<sup>2</sup>+2 = 3&#8729;4+2 = 12+2 = 14
3&#8729;2<sup>4-1</sup> + 4 - 1 = 3&#8729;2<sup>3</sup>+3 = 3&#8729;8+3 = 24+3 = 27
3&#8729;2<sup>5-1</sup> + 5 - 1 = 3&#8729;2<sup>3</sup>+1 = 3&#8729;16+4 = 48+5 = 52

It checks.

Edwin</pre>