Question 1090750
t^2+14+t24 
write it
{{{t^2 + 24t + 14 = 0}}}
This is not a perfect square and has no integer roots
Use quadratic formula to find t; 
{{{t = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}; where a=1; b=24; c=14
{{{t = (-24 +- sqrt( 24^2-4*1*14 ))/(2*1) }}}
{{{t = (-24 +- sqrt( 576-56 ))/(2) }}}
{{{t = (-24 +- sqrt( 520 ))/(2) }}} 
{{{t = (-24 +- 22.8)/(2) }}} 
Two solutions
 {{{t = (-24 + 22.8)/(2) }}}
t = {{{-1.2/2}}}
t = -.598
and 
 {{{t = (-24 - 22.8)/(2) }}}
t = {{{-46.8/2}}}
t = -23.4