Question 1090533
The equation for the balls' movement would be -1/2g(t²)+v(t)+1 in this case. So, we have:
h(t)=-4.9(3²)+v(3)+1, or
46=-4.9(9)+3v+1, or
3v=89.1
v=29.7 m/s. So,
h(t)=-4.9t²+29.7t+1
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The ball will hit the ground when h(t)=0, so:
0=-4.9t²+29.7t+1
Solve for t
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