Question 1090572
*[illustration xy.JPG].
.
.
.
{{{HYP=sqrt((-2)^2+4^2)=sqrt(4+16)=sqrt(20)=2sqrt(5)}}}
So,
{{{cos(theta)=-2/HYP}}}
.
.
{{{sin(theta)=4/HYP}}}
.
.
{{{tan(theta)=sin(theta)/cos(theta)}}}
.
.
{{{cot(theta)=1/tan(theta)}}}
.
.
{{{sec(theta)=1/sin(theta)}}}
.
.
{{{csc(theta)=1/cos(theta)}}}