Question 1090550
<br>You can also solve this using a single variable, instead of using three variables and solving a system of three equations.  This can require a bit more time to set up the problem correctly; but once it is set up it often requires less time to reach the solution.<br>
The given information compares Huey's amount to Louie's amount and then compares Dewey's amount to Huey's amount.  So a good place to start is with Louie's amount.<br>
Let x = Louie's amount
Then 2x+4 = Huey's amount (4 more than two times as much as Louie)
And 2(2x+4)-4 = 4x+4 = Dewey's amount (4 less than two times as much as Huey)<br>
Then the total amount is 85, so
{{{x + (2x+4) + (4x+4) = 85}}}
{{{7x+8 = 85}}}
{{{7x = 77}}}<br>
So Louie's amount is x = 11;
Huey's amount is 2x+4 = 22+4 = 26;
Dewey's amount is 4x+4 = 44+4 = 48.<br>
It's always a good idea to make sure your answers are correct...
11+26+48 = 85... Good!!