Question 1090520
{{{y=a(x+4)(x-1)}}}
Then,
{{{-8=a(0+4)(0-1)}}}
{{{-8=a(-4)}}}
{{{a=2}}}
So,
{{{y=2(x+4)(x-1)}}}
{{{y=2(x^2+3x-4)}}}
{{{y=2x^2+6x-8}}}

.
.
.
*[illustration T9.JPG].