Question 1090505
Use x,y nomenclature,
{{{y=(x-2)^2+3}}}
Interchange x and y, solve for y,
{{{x=(y-2)^2+3}}}
{{{(y-2)^2=x-3}}}
{{{y-2=0 +- sqrt(x-3)}}}
{{{y=2 +- sqrt(x-3)}}}
{{{f^(-1)=2 +- sqrt(x-3)}}}