Question 1090487
{{{A=(matrix(3,3,
2,-1,3,
1,1,1,
3,1,-1))}}}
{{{abs(A)=-14}}}
,
,
,
{{{A[x]=(matrix(3,3,
4,-1,3,
2,1,1,
2,1,-1))}}}
{{{abs(A[x])=-12}}}
,
,
,
{{{A[y]=(matrix(3,3,
2,4,3,
1,2,1,
3,2,-1))}}}
{{{abs(A[y])=-4}}}
,
,
,
{{{A[z]=(matrix(3,3,
2,-1,4,
1,1,2,
3,1,2))}}}
{{{abs(A[z])=-12}}}
,
,
,
So,
{{{x=abs(A[x])/abs(A)=(-12)/(-14)=6/7}}}
{{{y=abs(A[y])/abs(A)=(-4)/(-14)=2/7}}}
{{{z=abs(A[z])/abs(A)=(-12)/(-14)=6/7}}}