Question 1090451

if {{{r(x)=4x-4}}} and {{{s(x)=3x}}},then

 {{{(r-s)(x)=r(x)-s(x)}}}

 {{{(r-s)(x)=4x-4-3x}}}

{{{(r-s)(x)=x-4}}}



{{{(r+s)(x)=r(x)+s(x)}}}

{{{(r+s)(x)=4x-4+3x}}}

{{{(r+s)(x)=7x-4}}}

 and 

{{{(r*s)(-1)}}}=....first find {{{(r*s)(x)}}}

{{{(r*s)(x)=(4x-4)3x}}}

{{{(r*s)(x)=12x^2-12x}}}

now find {{{(r*s)(-1)}}}

{{{(r*s)(-1)=12(-1)^2-12(-1)}}}

{{{(r*s)(-1)=12(1)+12}}}

{{{(r*s)(-1)=12+12}}}

{{{(r*s)(-1)=24}}}