Question 1090398
First off it's Q2 then {{{cos(theta)<0}}},
So then,
{{{sin^2(theta)+cos^2(theta)=1}}}
{{{sin^2(theta)+(-5/13)^2=1}}
{{{sin^2(theta)=1-25/169}}}
{{{sin^2(theta)=144/169}}}
{{{sin(theta)=0 +- 12/13}}}
Since it's Q2, {{{sin(theta)>0}}}
{{{highlight(sin(theta)=12/13)}}}
and
{{{tan(theta)=(12/13)/(-5/13)}}}
{{{highlight(tan(theta)=-12/5)}}}