Question 96870
{{{y=abs(-3x+5)}}} Start with the given equation


Break up the absolute value equation into two parts. Remember {{{abs(x)=a}}} becomes {{{x=a}}} or {{{x=-a}}}


{{{-y=-3x+5}}} or {{{y=-3x+5}}} 


{{{-1(-y)=-1(-3x+5)}}}For the first equation, multiply both sides by -1 to make y positive


{{{y=3x-5}}} Distribute



So we now have these two equations



{{{y=3x-5}}} or {{{y=-3x+5}}} 




Now graph the two equations




{{{ graph( 500, 500, -10, 10, -10, 10, 3x-5, -3x+5) }}} Graph of {{{y=3x-5}}} (red) and {{{y=-3x+5}}}(green)



Remember, an absolute value graph is in a "V" shape, so that means the graph {{{y=-3x+5}}} is the left branch and {{{y=3x-5}}} is the right branch. 



So just erase the portions of the graph below the intersection like this



{{{ graph( 500, 500, -10, 10, -10, 10, abs(-3x+5)) }}} Graph of {{{y=abs(-3x+5)}}}