Question 466282
<br>If the smallest of the 6 consecutive even numbers is m+1, then we need to add 2 5 times to get to the last of them:
{{{(m+1)+5*2=m+11}}}
Then the average of any set of numbers in which the difference between successive numbers is constant (the numbers form an arithmetic progression, or arithmetic sequence) is just the average of the first and last numbers:
{{{((m+1)+(m+11))/2 = m+6}}}