Question 1090262
{{{ y=sin(x) }}}, {{{ -2pi <= x <= 2pi }}}

The domain is the possible x values and is specified as {{{ -2pi <= x <= 2pi }}}  ( without qualifications, the domain of "sin(x)" is all real x values, however,  some will say this problem is <em>domain restricted</em> to {{{-2pi <= x <= 2pi }}} )
The range is all the values y can take on for values of x in its domain.  Since y=sin(x) can only take on values between -1 and 1 inclusive, the range is {{{ -1 <= y <= 1 }}}  
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The y intercept is found by setting x=0:   y = sin(0) = 0
    y intercept is {{{ highlight(0) }}}

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The x intercept(s) are found by setting y=0:   0 = sin(x)
Where does sin(x) = 0?    

At {{{ x=0 }}}, {{{ x=-pi }}}, {{{ x=-2pi}}}, {{{ x=pi}}}, and {{{ x=2pi }}}

x intercepts are {{{ highlight(x=0) }}}, {{{ highlight(x=-pi) }}}, {{{ highlight(x=-2pi)}}}, {{{ highlight(x=pi)}}}, and {{{ highlight(x=2pi) }}}
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A graph may help with the visualization:
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{{{ 
  graph( 300, 300, -6.283, 6.283, -2, 2, sin(x) )

}}}