Question 1090248
1.)equation of the inverse?

{{{f(x)=3x^2+5}}}

since {{{f(x)=y}}}, we have

{{{y=3x^2+5}}} .......swap {{{x}}} and {{{y}}}

{{{x=3y^2+5}}}............solve for  {{{y}}}

{{{x-5=3y^2}}}

{{{(x-5)/3=y^2}}}

{{{y=sqrt((x-5)/3)}}}

{{{y}}}=± {{{sqrt(x - 5)/sqrt(3)}}}

{{{f^-1(x)}}}=± {{{sqrt(x - 5)/sqrt(3)}}}