Question 1090244

{{{x^2+3x+c}}}

recall the rule:{{{(a+b)^2= a^2+2ab+b^2}}}

so, {{{c=b^2}}}

since {{{a=1}}} and
{{{2ab=3}}} -> {{{b=3/2}}}

then, since {{{c=b^2}}} we have

{{{c=(3/2)^2}}}

{{{c=9/4}}}